If x+ y=18 and xy= 72, what is the value of \( \Large x^{2} + y^{2} \)
Correct Answer: Description for Correct answer:
x + y = 18
Because, \( \Large x^{2} + y^{2} = \left(x + y\right)^{2} - 2xy \)
\( \Large = \left(18\right)^{2} - 2 \times 72 = 324 - 144 = 180 \)
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