A) -2 |
B) \( \Large - \frac{a}{2} \) |
C) \( \Large \frac{2}{a} \) |
D) \( \Large - \frac{2}{a} \) |
D) \( \Large - \frac{2}{a} \) |
Given, \( \Large x + \frac{a}{x} = 1 \)
=> \( \Large x^{2} + a = x \) ...(i)
=> \( \Large x^{2} - x = -a \) ...(ii)
Now, \( \Large \frac{x^{2} + x + a}{x^{3} - x^{2}} = \frac{x + x}{x \left(x^{2} - x\right) } \) [from Eq. (i)]
= \( \Large \frac{2x}{x \left(-a\right) } \) [from Eq. (ii)]
= \( \Large \frac{2}{-a} \)