A) If x>y |
B) \( \Large If \ x\ge y \) |
C) lf x |
D) \( \Large If \ x \le y \) |
D) \( \Large If \ x \le y \) |
\( \Large x^{2} - 16 = 0 \)
=> \( \Large x^{2} = 16 = x = \sqrt{16} = \pm 4 \)
and \( \Large y^{2} - 9y + 20 = 0 \)
\( \Large y^{2} - 4y - 5y + 2 = 0 \)
=> \( \Large y \left(y-4\right) - 5 \left(y-4\right) = 0 \)
=> y = 5, 4
\( \Large y \ge \ x \ or \ x \le y \)