A) If x>y |
B) \( \Large If x\ge y \) |
C) lfx |
D) If x = y or relation cannot be established |
D) If x = y or relation cannot be established |
\( \Large x^{2} - 32 = 112 \)
=> \( \Large x^{2} = 112 + 32 => x^{2} = 144 \)
Therefore, x = \( \Large \pm \) 12
and \( \Large y - \sqrt{169} = 0 \)
=>\( \Large y = \sqrt{169} => y = \pm 13 \)
Therefore, Relation cannot be established