A) If x>y |
B) \( \Large If \ x \ge y \) |
C) lfx |
D) \( \Large If \ x \le y \) |
D) \( \Large If \ x \le y \) |
\( \Large x^{2} - 365 = 364 \)
=>\( \Large x^{2} = 364 + 365 \)
Therefore, \( \Large x = \sqrt{729} = \pm 27 \)
and \( \Large y - \sqrt{324} = \sqrt{81} => y - 18 = 9 \)
Therefore, y = 27
So, \( \Large y\ge x \ or \ x \le y \) because y = 27 and x = -27 and x = 27