Topics
\( \Large x^{2}+x-20=0; y^{2}-y-30=0 \)
|
A) If x>y |
|
B) \( \Large If \ x \ge y \) |
|
C) lfx |
|
D) \( \Large If \ x \le y \) |
Correct Answer:
| D) \( \Large If \ x \le y \) |
Description for Correct answer:
\( \Large x^{2}+x-20=0 \) [by factorisation method]
= \( \Large x^{2}+5x-4x-20=0 \)
= \( \Large x \left(x+5\right)-4 \left(x+5\right)=0 \)
= \( \Large \left(x+5\right) \left(x-4\right)=0 \)
Therefore, x = -5 or 4
and \( \Large y^{2}-y-30=0 \)
= \( \Large y^{2}-6y+5y-30=0 \)
= \( \Large y \left(y-6\right)+5 \left(y-6\right)=0 \)
= \( \Large \left(y-6\right) \left(y+5\right)=0 \)
Therefore, y = 6 or -5
Hence, \( \Large y \ge x \ or \ x \le y \)
Part of solved Quadratic Equations questions and answers : >> Elementary Mathematics >> Quadratic Equations
Comments
Similar Questions
1). \( \Large 225x^{2}-4=0; \sqrt{225y}+2=0 \)
| ||||
2). \( \Large \frac{4}{\sqrt{x}}+\frac{7}{\sqrt{x}}=\sqrt{x;} \) \( \Large y^{2}-\frac{ \left(11\right)^{\frac{5}{2}} }{\sqrt{y}} =0 \)
| ||||
3). \( \Large x^{2}-365=364; y-\sqrt{324}=\sqrt{81} \)
| ||||
4). \( \Large 3x^{2}+8x+4=0; 4y^{2}-19y+12=0 \)
| ||||
5). \( \Large x^{2}-x-12=0; y^{2}+5y+6=0 \)
| ||||
6). \( \Large x^{2}-8x+15=0; y^{2}-3y+2=0 \)
| ||||
7). \( \Large x^{2}-32=112; y-\sqrt{169}=0 \)
| ||||
8). \( \Large x-\sqrt{121}=0; y^{2}-121=0 \)
| ||||
9). \( \Large x^{2}-16=0; y^{2}-9y+20=0 \)
| ||||
10). If \( \Large x^{2} = 6 + \sqrt{6+\sqrt{6 + \sqrt{6+.... ...... \infty}}} \) then what is one of the values of x equal to?
|
