A) \( \Large -\frac{1}{2} \) |
B) -1 |
C) 1 |
D) 2 |
C) 1 |
Given, one roots of \( \Large x^{2}-6kx+5=0 \ is \ 5 \)
Therefore, x = 5 satisfies \( \Large x^{2}-6kx+5=0 \)
= \( \Large 5^{2}-6 \times k \times 5+5=0 \)
= \( \Large 25-30k+5=0 \)
=> 30 - 30k = 0
=> 30k = 30
Therefore, k = 1
1). If one of the roots of quadratic equation \( \Large 7x^{2}-50x+k=0 \) is 7, then what is the value of k?
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2). Find the roots of the equation \( \Large 2x^{2}-11x+15=0 \)
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3). The quadratic equation whose roots are 3 and -1, is
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4). \( \Large x^{2}+x-20=0; y^{2}-y-30=0 \)
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5). \( \Large 225x^{2}-4=0; \sqrt{225y}+2=0 \)
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6). \( \Large \frac{4}{\sqrt{x}}+\frac{7}{\sqrt{x}}=\sqrt{x;} \) \( \Large y^{2}-\frac{ \left(11\right)^{\frac{5}{2}} }{\sqrt{y}} =0 \)
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7). \( \Large x^{2}-365=364; y-\sqrt{324}=\sqrt{81} \)
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8). \( \Large 3x^{2}+8x+4=0; 4y^{2}-19y+12=0 \)
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9). \( \Large x^{2}-x-12=0; y^{2}+5y+6=0 \)
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10). \( \Large x^{2}-8x+15=0; y^{2}-3y+2=0 \)
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