If one root of \( \Large x^{2}-6kx+5=0 \) is 5, find the value of k.


A) \( \Large -\frac{1}{2} \)

B) -1

C) 1

D) 2

Correct Answer:
C) 1

Description for Correct answer:

Given, one roots of \( \Large x^{2}-6kx+5=0 \  is \  5 \)

Therefore, x = 5 satisfies \( \Large x^{2}-6kx+5=0 \)

= \( \Large 5^{2}-6 \times k \times 5+5=0 \)

= \( \Large 25-30k+5=0 \)

=> 30 - 30k = 0

=> 30k = 30

Therefore, k = 1


Part of solved Quadratic Equations questions and answers : >> Elementary Mathematics >> Quadratic Equations








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