• If one root of $$\Large x^{2}-6kx+5=0$$ is 5, find the value of k.
 A) $$\Large -\frac{1}{2}$$ B) -1 C) 1 D) 2

 C) 1

Given, one roots of $$\Large x^{2}-6kx+5=0 \ is \ 5$$

Therefore, x = 5 satisfies $$\Large x^{2}-6kx+5=0$$

= $$\Large 5^{2}-6 \times k \times 5+5=0$$

= $$\Large 25-30k+5=0$$

=> 30 - 30k = 0

=> 30k = 30

Therefore, k = 1

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