A) 4 h |
B) 6 h |
C) 8 h |
D) 10 h |
B) 6 h |
Let time taken by B = x
Efficiency \( \propto \) \( \Large \frac{1}{Time \ taken} \)
So, if B is 100% efficient. then A is 80% efficient.
SO, \( \Large \frac{80}{100} \)= \( \Large \frac{x}{15/2} \)
x=6 h