A) 64 min |
B) 80 min |
C) 96 min |
D) 120 min |
D) 120 min |
Part filled by tap A in 1 min = \( \Large \frac{1}{60} \)
Let tap B fills the tank in x min
Then, part filled by tap, B in 1 min = \( \Large \frac{1}{x} \)
According to the question,
= \( \Large \frac{1}{60} \) + \( \Large \frac{1}{x} \) = \( \Large \frac{1}{40} \)
= \( \Large \frac{1}{x} \) = \( \Large \frac{1}{40} \) - \( \Large \frac{1}{60} \)
=> \( \Large \frac{1}{x} \) = \( \Large \frac{3-2}{120} \) => \( \Large \frac{1}{x} \) = \( \Large \frac{1}{120} \)
Therefore, Tap B can fill the tank in 120 min.