A) \( \Large 4\frac{1}2{} \) h |
B) 7 h |
C) 6 h |
D) 10 h |
A) \( \Large 4\frac{1}2{} \) h |
Part filled by A in 1 h = \( \Large 3 \times \frac{1}{18} \)
Part filled by B in 1 h = \( \Large \frac{1}{6} \)
Part filled by (A + B) =
\( \Large \frac{1}{18} \)+\( \Large \frac{1}{6} \) = \( \Large \frac{1+3}{18} \) = \( \Large \frac{4}{18} \) = \( \Large \frac{2}{9} \)
Here, both the pipes together will fill the tank in \( \Large \frac{9}{2} \) h or \( \Large 4\frac{1}{2} \)