4 men and 6 women get Rs.1600 by doing a piece of work in 5 days. 3 men and 7 women get Rs.1740 by doing the same work in 6 days. In how many days, 7 men and 6 women can complete the same work getting Rs.3760?


A) 6 days

B) 8 days

C) 10 days

D) 12 days

Correct Answer:
B) 8 days

Description for Correct answer:

In 5 days, (4 men + 6 women) get = Rs.1600

Therefore, In 1 day, (4 men + 6 women) get

= \( \Large \frac{1600}{5} \) = Rs.320 ...(i)

In 1 day, number of persons to get Re.1

= \( \Large \frac{320}{4 men + 6 women}\) ...(ii)

Similarly, in second condition,

In 1 day, number of persons to get Re.1

= \( \Large \frac{1740}{6 \times \left(3 men + 7 women\right) }

= \frac{290}{3 men + 7 women} \) ...(iii)

From Eqs. (ii) and (iii), we get

\( \Large \frac{320}{3 men + 7 women} = \frac{290}{3 men + 7 women} \)

96 men + 224 women = 116 men + 174 women

= 20 men = 50 women

= \( \Large \frac{Man}{Woman} \) = \( \Large \frac{5}{2} \)

Therefore, 1 woman = \( \Large \frac{2}{5}man \)

From Eq. (i), in 1 day,

\( \Large \left(4 men + 6 women\right) = \left(4 men + 6 \times \frac{2}{5} men\right) \)

= \( \Large \frac{32}{5} \) men get Rs.320

Therefore, In 1 day, 1 man get = \( \Large \frac{320 \times 5}{32} \) = Rs.50

Therefore, In 1 day, 1 woman get = \( \Large \frac{50 \times 2 }{5} \) = Rs.20

Therefore, In 1 day, \( \Large \left(7 men + 6 women\right) \) get

\( \Large 7 \times 50 + 6 \times 20 = Rs.470 \)

Therefore, Required number of days = \( \Large \frac{3760}{470} \) = 8 days


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