The remainder when \( \Large 9^{19}+6 \) is divided by 8 is
Correct Answer: Description for Correct answer:
Required remainder = \( \Large 9^{19} \) + 6
= \( \Large (1)^{19}+6 \)=9
[ 8=9-1,so replaced by 1]
We have = \( \Large \frac{(9)^{19}+6}{8} \)
=> \( \Large \frac{(8+1)^{19}+6}{8} \) => \( \Large \frac{1^{19}+6}{8} \)
=> \( \Large \frac{1+6}{8}=\frac{7}{8} \)
Remainder = 7
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