Sum of first 15 multiples of 8 is
Correct Answer: Description for Correct answer:
First 15 multiple of 8 are
8, 16, 24,....., 120
So, 8 (1, 2, 3, 4,.....,15) + 1
Their sum = 8 \( \Large \left[ \frac{n(n+1)}{2} \right] \)
=8 \( \Large \left[ \frac{15(15+1)}{2} \right] \)
= \( \Large 8\times 15\times 8 \)=960
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