If a train 500 meter long enters a tunnel 0.5 km long at 10.05 am. and is completely out of it at 10.10 a.m., then speed of the train is
Correct Answer: Description for Correct answer:
v = \( \Large \frac{0.5+0.5}{\frac{5}{60}} \) km/hr = 12 kmph
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