1). 150 m long train running with the speed of 90 km/h to cross a bridge in 26 s. What is the length of the bridge?
A). 500 m |
B). 600 m |
C). 659 m |
D). 550 m |
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2). A train travelling at a speed of 30 m/s crosses a 600 m long platform in 30 s. Find the length of the train.
A). 120 m |
B). 150 m |
C). 200 m |
D). 300 m |
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3). A 240 m long train crosses a platform of equal length in 27 s. What is the speed of the train in km/h?
A). 48 km/h |
B). 60 km/h |
C). 56 km/h |
D). 64 km/h |
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4). A train crossed a platform in 43 s. The length of the train is 170 m . What is the speed of the train?
A). 233 km/h |
B). 243 km/h |
C). 265 km/h |
D). Cannot be determined |
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5). A train crosses a platform in 30s travelling with a speed of 60 km/h. If the length of the train be 200 m, then the length of the platform is
A). 420 m |
B). 500 m |
C). 300 m |
D). 250 m |
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6). A train crosses a bridge of length 150 m in 15 s and a man standing on it in 9 s. The train is travelling at a uniform speed. Length of the train is
A). 225 m |
B). 200 m |
C). 135 m |
D). 90 m |
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7). A train moving with uniform speed crosses a pole in 2s and a 250 m long bridge in 7s. Find the length of the train.
A). 150 m |
B). 120 m |
C). 100 m |
D). 80 m |
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8). A train travelling with uniform speed crosses two bridges of lengths 300 m and 240 m in 21 s and 18 s, respectively. Find the speed of the train.
A). 72 km/h |
B). 68 km/h |
C). 65 km/h |
D). 60 km/h |
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9). The relative speed of a train in respect of a car is 90 km/h when train and car are moving opposite to each other. Find the actual speed of train, if car is moving with a speed of 15 km/h.
A). 80 km/h |
B). 105 km/h |
C). 75 km/h |
D). 100 km/h |
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10). A 440 m long train is running at 240 km/h. In what time will it pass a man running in the direction opposite to that of the train at 24 km/h?
A). 9 s |
B). 6 s |
C). 12 s |
D). 4 s |
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A) 150 m

B) 200 m

C) 300 m

D) 350 m

Correct Answer:

Description for Correct answerSpeed of train

= \( \Large \frac{ Length \ of \ train }{ Time \ taken \ to \ cross \ the \ stationary \ object } \)

Therefore, Length of train = Speed of train X Time taken to cross the stationary object

= \( \Large \frac{72 \times 5 \times 15}{18} \) = 300 m