A) 12 |
B) 6 |
C) 8 |
D) 10 |
C) 8 |
Average of 8 numbers = 14
Sum of 8 numbers = \( \Large 14 \times 8 = 112 \)
Similarly, average of 6 numbers = 16
Sum of 6 numbers = \( \Large 16 \times 6 = 96 \)
Therefore, Sum of remaining two numbers = Sum of 8 numbers - Sum of 6 numbers
= 112 - 96 = 16
Average = \( \Large \frac{Sum \ of \ two \ number}{2} = \frac{16}{2} = 8 \)