\( \Large tan \theta = \frac{AB}{EB} = \frac{ \left(AC-BC\right) }{DC} \) = \( \Large \frac{ \left(\frac{26}{3}-6\right) }{\frac{8}{\sqrt{3}}} \) = \( \Large \frac{\frac{ \left(26-18\right) }{3}}{\frac{8}{\sqrt{3}}} = \frac{1}{\sqrt{3}} \) = \( \Large \theta = tan^{-1} \left(\frac{1}{\sqrt{3}}\right) = 30 ^{\circ} \)