ABC is a triangle and the sides AB, BC and CA are produced to E, F and G respectively. If \( \angle CBE = \angle ACF = 130 ^{\circ} \), then the value of \( \angle GAB \) is

A) \( 130 ^{\circ} \)
B) \( 90 ^{\circ} \)

C) \( 100 ^{\circ} \)
D) \( 80 ^{\circ} \)

Correct answer:
C) \( 100 ^{\circ} \)

Description for Correct answer:


W.K.T. sum of three exterior angles = \( 360 ^{\circ} \)

Therefore, \( \angle GAB = 360 ^{\circ} - \left(130 ^{\circ} +130 ^{\circ} \right) = 100 ^{\circ} \)

Please provide the error details in above question

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