The percentage increase in the surface area of a cube when each side is doubled is :

A) 1.5

B) 0.5

C) 2

D) 3

Correct answer:
D) 3

Description for Correct answer:

Surface area of a cube = \( 6 X \left(side\right)^{2} \)

Let the side of cube = 'a'

then its surface area = \( 6a^{2} \)

new side of a cube = 2a

then its surface area = \( 6 \left(2a\right)^{2} = 24a^{2} \)

Therefore, Percentage increase = \( \Large \frac{24a^{2}-6a^{2}}{6a^{2}} \times 100 \)

= \( \Large  \frac{18a^{2}}{6a^{2}} \times 100 = 300\% \)



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