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The present population of village P is 2 times the population of village Q an year ago. If after a year, the population of village Q will be 3528 increasing at a constant rate of 20% every year, what is the present population of village P?
A) 4200
B) 3250
C) 4900
D) 4650
E) 3850
Correct answer:
C) 4900
Description for Correct answer:
An year ago, let the population of village Q = x
Then, the presenet population of village P = 2x
Accordig to question,
\( 3528 = x \times \frac{120}{100} \times \frac{120}{100} \)
\( x = 2450 \)
\( = 2 \times 2450 = 4900 \)
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