If \( \Large \frac{2a+b}{a+4b}=3 \), then find the value of \( \Large \frac{a+b}{a+2b} \)

A) \( \Large \frac{5}{9} \)
B) \( \Large \frac{2}{7} \)

C) \( \Large \frac{10}{9} \)
D) \( \Large \frac{10}{7} \)

Correct answer:
C) \( \Large \frac{10}{9} \)

Description for Correct answer:
\( \Large \frac{2a+b}{a+4b}=3 \)

\( \Large 2a + b = 3 \left(a+4b\right) \)

\( \Large 2a + b = 3a + 12b \)

=> \( \Large -a = 11b \)

a = -11b

Therefore, \( \Large \frac{a+b}{a+2b} \)

=> \( \Large \frac{-11b+b}{-11b+2b} \)

= \( \Large \frac{-10b}{-9b} = \frac{10}{9} \)

Please provide the error details in above question

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