A tank has two inlets : A and B. A alone takes 2 hours and B alone takes 3 hours to fill the empty tank completely when there is no leakage. A leakage was caused which would empty the full tank completely in 'x' hours when no inlet is open. Now, when only inlet A was opened, it took 3 hours to fill the empty tank completely. How much time will B alone take to fill the empty tank completely ? (in hours)

A) 4.5

B) 7.5

C) 3

D) 6

Correct answer:
D) 6

Description for Correct answer:
when pipe A is opened, part of the tank emptied by leak in 1 hour

= \( \Large \frac{1}{3} - \frac{1}{2} = \frac{2 - 3}{6} = - \frac{1}{6} \)

\( \Large \therefore \) Time taken in empting whole tank = 6 hours

\( \Large \therefore \) Part of the tank filled in 1 hour by pipe B

= \( \Large \frac{1}{3} - \frac{1}{6} = \frac{2 - 1}{6} = \frac{1}{6} \)

\( \Large \therefore \) Required time = 6 hours


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