In the following question two equations numbered I and II are given. You have to solve both the equations and Give answer

I. \( \Large x^{2} \) + x - 12 = 0

II. \( \Large y^{2} \) - 5y + 6 = 0

A) x > y

B) x \( \Large \geq \) y

C) x < y

D) x \( \Large \leq \) y

Correct answer:
D) x \( \Large \leq \) y

Description for Correct answer:
I. \( \Large x^{2} \) + x - 12 = 0

=> \( \Large x^{2} \) + 4x - 3x - 12 = 0

=> x ( x + 4 ) - 3 ( x + 4 ) = 0

=> ( x - 3 ) ( x + 4 ) = 0

=> x = 3 or -4

II. \( \Large y^{2} \) - 5y + 6 = 0

=> \( \Large y^{2} \) - 3y - 2y + 6 = 0

=> y ( y - 3 ) - 2( y - 3 ) = 0

=> ( y - 2 ) ( y - 3 ) = 0

=> y = 2 or 3

Please provide the error details in above question

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