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In the following question two equations numbered I and II are given. You have to solve both the equations and Give answer
I.\( \Large x^{2} \) - 7x + 12 = 0
II.\( \Large y^{2} \) + y - 12 = 0
A) x > y
B) x \( \Large \geq \) y
C) x < y
D) x \( \Large \leq \) y
Correct answer:
B) x \( \Large \geq \) y
Description for Correct answer:
I. \( \Large x^{2} \) - 4x - 3x + 12 = 0
=> x ( x - 4 ) - 3 ( x - 4 ) = 0
=> ( x - 3 )( x - 4 ) = 0
\( \Large \therefore \) x = 3 or 4
II. \( \Large y^{2} \) + 4y - 3y - 12 = 0
=> y ( y + 4 ) - 3 ( y + 4 ) = 0
=> ( y - 3 )( y + 4 ) = 0
\( \Large \therefore \)y = 3 or -4
Clearly, x \( \Large \geq \) y
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