In the following question two equations numbered I and II are given. You have to solve both the equations and Give answer

I.\( \Large x^{2} \) - 7x + 12 = 0

II.\( \Large y^{2} \) + y - 12 = 0

A) x > y

B) x \( \Large \geq \) y

C) x < y

D) x \( \Large \leq \) y

Correct answer:
B) x \( \Large \geq \) y

Description for Correct answer:
I. \( \Large x^{2} \) - 4x - 3x + 12 = 0

=> x ( x - 4 ) - 3 ( x - 4 ) = 0

=> ( x - 3 )( x - 4 ) = 0

\( \Large \therefore \) x = 3 or 4

II. \( \Large y^{2} \) + 4y - 3y - 12 = 0

=> y ( y + 4 ) - 3 ( y + 4 ) = 0

=> ( y - 3 )( y + 4 ) = 0

\( \Large \therefore \)y = 3 or -4

Clearly, x \( \Large \geq \) y

Please provide the error details in above question

Recent Activities
Home About Us Terms and Conditions Privacy Policy Contact us