In the following question two equations numbered I and II are given. You have to solve both the equations and Give answer

I. \( \Large 2x^{2} \) + 11x + 12 = 0

II. \( \Large 5y^{2} \) + 27y + 10 = 0

A) x > y

B) x \( \Large \geq \) y

C) x < y
D) x = y or the relationship cannot be established.

Correct answer:
D) x = y or the relationship cannot be established.

Description for Correct answer:
\( \Large 2x^{2} \) + 11x + 12 = 0

=> 2 \( \Large x^{2} \) + 8x + 3x + 12 = 0

=> 2x ( x + 4 ) + 3 ( x + 4 ) = 0

=> ( x + 4 )( 2x + 3 ) = 0

=> x = -4 or -\( \Large \frac{3}{2} \)

II. 5\( \Large y^{2} \) + 27y + 10 = 0

=> 5\( \Large y^{2} \) + 25y + 2y + 10 = 0

=> 5y ( y + 5 ) + 2 ( y + 5 ) = 0

=> ( y + 5 )( 5y + 2 ) = 0

=> y = -5 or -\( \Large \frac{2}{5} \)

Please provide the error details in above question

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