In the following question two equations numbered I and II are given. You have to solve both the equations and Give answer

I. \( \Large x^{2} \) - 7x + 12 = 0

II. \( \Large y^{2} \) - 12y + 32 = 0

A) x > y

B) x \( \Large \geq \) y

C) x < y

D) x \( \Large \leq \) y

Correct answer:
D) x \( \Large \leq \) y

Description for Correct answer:
I. \( \Large x^{2} \) - 7x + 12 = 0

=> \( \Large x^{2} \) - 4x - 3x + 12 = 0

=> x ( x - 4 ) - 3 ( x - 4 ) = 0

=> ( x - 3 )( x - 4 ) = 0

=> x = 3 or 4

II. \( \Large y^{2} \) - 12y + 32 = 0

=> \( \Large y^{2} \) - 8y - 4y + 32 = 0

=> y ( y - 8 ) - 4 ( y - 8 ) = 0

=> ( y - 4 )( y - 8 ) = 0

=> y = 4 or 8

Clearly, x \( \Large \leq \) y

Please provide the error details in above question

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