In the following question two equations numbered I and II are given. You have to solve both the equations and Give answer

I. \( \Large x^{2} \) + 13x = - 42

II. \( \Large y^{2} \) + 16y + 63 = 0

A) X > Y

B) X \( \Large \geq \) Y

C) X < Y

D) X \( \Large \leq \) Y

Correct answer:
B) X \( \Large \geq \) Y

Description for Correct answer:
I. \( \Large x^{2} \) + 13x + 42 = 0

=> \( \Large x^{2} \) + 7x + 6x + 42 = 0

=> x ( x + 7 ) + 6 ( x + 7 ) = 0

=> ( x + 6 ) ( x + 7 ) = 0

\( \Large \therefore \) x = -6 or -7

II. \( \Large y^{2} \) + 16y + 63 = 0

=> \( \Large y^{2} \) + 9y + 7y + 63 = 0

=> y ( y + 9 ) + 7 ( y + 9 ) = 0

=> ( y + 9 ) ( y + 7 ) = 0

\( \Large \therefore \) y = -9 or -7

Clearly, x \( \Large \geq \) y

Please provide the error details in above question

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