In the following question two equations numbered I and II are given. You have to solve both the equations and Give answer

I. \( \Large x^{2} \) + 9x +20 = 0

II. \( \Large y^{2} \) + 7y + 12 = 0

A) X > Y

B) X \( \Large \geq \) Y

C) X < Y

D) X \( \Large \leq \) Y

Correct answer:
D) X \( \Large \leq \) Y

Description for Correct answer:
I. \( \Large x^{2} \) + 9x + 20 = 0

=> \( \Large x^{2} \) + 5x + 4x + 20 = 0

=> x ( x + 5 ) + 4 ( x + 5 ) = 0

=> ( x + 4 ) ( x + 5 ) = 0

x = -4 or -5

II. \( \Large y^{2} \) + 7y + 12 = 0

=> \( \Large y^{2} \) + 4y + 3y + 12 = 0

=> y ( y + 4 ) + 3 ( y + 4 ) = 0

=> ( y + 3 ) ( y + 4 ) = 0

\( \Large \therefore \) y = -3 or -4

Clearly, x \( \Large \leq \) y

Please provide the error details in above question

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