In the following question two equations numbered I and II are given. You have to solve both the equations and Give answer

I. \( \Large x^{2} \) - 14x + 48 = 0

II. \( \Large y^{2} \) + 6 = 5y

A) X > Y

B) X \( \Large \geq \) Y

C) X < Y

D) X \( \Large \leq \) Y

Correct answer:
A) X > Y

Description for Correct answer:
I. \( \Large x^{2} \) - 14x + 48 = 0

=> \( \Large x^{2} \) - 8x - 6x + 48 = 0

=> x ( x - 8 ) - 6 ( x - 8 ) = 0

=> ( x - 6 ) ( x - 8 ) = 0

x = 6 or 8

II. \( \Large y^{2} \) - 5y + 6 = 0

=> \( \Large y^{2} \) - 3y - 2y + 6 = 0

=> y ( y - 3 ) - 2 ( y - 3 ) = 0

=> ( y - 2 ) ( y - 3 ) = 0

\( \Large \therefore \) y = 2 or 3

Clearly, x > y

Please provide the error details in above question

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