In the following questions two equations I and II are given. You have to solve both the equations and Give answer

I. \( \Large 6x^{2} \) + 13x + 5 = 0

II. \( \Large 9y^{2} \) + 22y + 8 = 0


A) x > y

B) x \( \Large \leq \) y

C) x < y

D) x = y or relationship between x and y cannot be established

Correct answer:
D) x = y or relationship between x and y cannot be established

Description for Correct answer:
I. 6 \( \Large x^{2} \) + 13x + 5 = 0

=> 6 \( \Large x^{2} \) + 10x + 3x + 5 = 0

=> 2x ( 3x + 5 ) + 1 ( 3x + 5 ) = 0

=> ( 3x + 5 ) ( 2x + 1 ) = 0

=> x = \( \Large \frac{-5}{3} \) or \( \Large - \frac{1}{2} \)

II. 9 \( \Large y^{2} \) + 22y + 8 = 0

=> 9 \( \Large y^{2} \) + 18y + 4y + 8 = 0

=> 9y ( y + 2 ) + 4 ( y + 2 ) = 0

=> ( y + 2 ) ( 9y + 4 ) = 0

=> y = -2 or \( \Large \frac{-4}{9} \)


Please provide the error details in above question