In the following questions two equations I and II are given. You have to solve both the equations and Give answer

I. \( \Large x^{2} \) + 91 = 20x

II. \( \Large 10y^{2} \) - 29y + 21 = 0

A) x > y

B) x \( \Large \leq \) y

C) x < y

D) x \( \Large \geq \) y

Correct answer:
A) x > y

Description for Correct answer:
I. \( \Large x^{2} \) - 20x + 91 = 0

=> \( \Large x^{2} \) - 13x - 7x + 91 = 0

=> x ( x - 13 ) - 7 ( x - 13 ) = 0

=> ( x - 7 ) ( x - 13 ) = 0

=> x = 7 or 13

II. 10 \( \Large y^{2} \) - 29y + 21 = 0

=> 10 \( \Large y^{2} \) - 15y - 14y + 21 = 0

=> 5y ( 2y - 3 ) - 7 ( 2y - 3 ) = 0

=> ( 2y - 3 ) ( 5y - 7 ) = 0

=> y = \( \Large \frac{3}{2} \) , \( \Large \frac{7}{5} \)

Clearly, x > y.

Please provide the error details in above question

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