In the following question two equations are given. You have to solve the equations and Give answer

I. \( \Large x^{2} \) + x - 6 = 0

II. \( \Large 2y^{2} \) - 13y + 21 = 0


A) x < y

B) x \( \Large \leq \) y

C) x = y

D) x \( \Large \geq \) y

Correct answer:
A) x < y

Description for Correct answer:
I. \( \Large x^{2} \) + x - 6 = 0

=> \( \Large x^{2} \) + 3x - 2x - 6 = 0

=> x ( x + 3 ) - 2 ( x + 3 ) = 0

=> ( x + 3) ( x - 2 ) = 0

\( \Large \therefore \) x = - 3 or 2

II. \( \Large 2y^{2} \) - 13y + 21 = 0

=> 2\( \Large y^{2} \) - 7y - 6y + 21 = 0

=> y ( 2y - 7 ) - 3 ( 2y - 7 ) = 0

=> ( 2y - 7 ) ( y -3 ) = 0

\( \Large \therefore \) y = \( \Large \frac{7}{2} \) or 3


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