Directions (32-36) : In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate option.
Give answer :
(1) \( x \le y \)
(2) \( x \ge y \)
(3) Relationship between X and y cannot be established
(4) x < y
(5) x > y 
I.\( 2x^{2} + 15x +27 = 0 \)
II. \( 2y^{2} + 7y +6 = 0 \)

A) \( x \le y \)
B) \( x \ge y \)

C) Relationship between X and y cannot be established
D) x < y

E) x > y

Correct answer:
D) x < y

Description for Correct answer:
I. \( \large 2x^{2} + 15x + 27 = 0 \)

\( \large 2x^{2} + 9x + 6x + 27 = 0 \)

\( \largex( 2x + 9) + 3(2x + 9)= 0 \)

\( \large (x + 3)(2x + 9) = 0 \)

\( \large x = -\frac{9}{2},-3 \)

II. \( \large 2y^{2} + 7y + 6 = 0 \)

\( \large 2y^{2} + 4y + 3y + 6 = 0 \)

\( \large 2y( y + 2) + 3(y + 2) = 0 \)

\( \large (y + 2)( 2y + 3) = 0 \)

\( \large y = -2, - \frac{3}{2} \)

So x < y

Please provide the error details in above question

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