Directions (32-36) : In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate option.
Give answer :
(1) \( x \le y \)
(2) \( x \ge y \)
(3) Relationship between X and y cannot be established
(4) x < y
(5) x > y 
I .\(x^{2} = 144 \)
II. \( y^{2} - 24y + 144 = 0 \)

A) \( x \le y \)
B) \( x \ge y \)

C) Relationship between X and y cannot be established
D) x < y

E) x > y

Correct answer:
A) \( x \le y \)

Description for Correct answer:
I. \( \large x^{2} = 144 \)

=>\( \large x = \sqrt{144} = \pm 12 \)

II. \( \large y^{2} - 24y + 144 = 0 \)

\( \large y^{2} - 12y-12y + 144 = 0 \)

\( \large y (y - 12) - 12 (y - 12) = 0 \)

\( \large (y - 12) (y - 12) = 0 \)

Y = 12

So. \( \large x \le y \)

Please provide the error details in above question

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