A boy walks at 4 Km/hr and reaches his school 5 minutes late. Next day he walks at 5 Km/hr and start at the same time, reaches his school 10 minutes early. How far the school is from his house



A) 4 kms

B) 5 kms

C) 6 kms

D) 3 kms

Correct answer:
B) 5 kms

Description for Correct answer:

\( \Large \frac{d}{4} - \frac{d}{5} \) = \(  \Large \frac{15}{60} \)

= \( \Large \frac{5d - 4d}{20} \) = \(  \Large \frac{15}{60} \)

= \( \Large \frac{d}{20}\) = \(  \Large \frac{1}{4} \)

=> d = 5 km





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