Description for Correct answer:
\( \large 1^2 + 2^2 + 3^2 + 4^2+ ..... +n^2 = \frac{n\left(n + 1\right)\left(2n + 1\right)}{6} \)

\( \large 1^2 + 2^2 + 3^2 + 4^2+ ..... +50^2 = \frac{50 \times 51 \times 101}{6}\)

=42925

Required average \( \large = \left( \frac{42925}{50} \right) = 858.5 \)