Description for Correct answer:
To find the HCF of 117, 156, 195

\( \Large \frac{156}{117}.\ \frac{39}{39}=0 \)

HCF of 117, 156 is 39

Again consider 39 and 195.

\( \Large \frac{195}{96} = 5 \)

HCF of 39 and 195 = 39

Hence, the required HCF is 39