Description for Correct answer:
\( \Large x^{2}+\frac{1}{x^{2}} = 102 \)

\( \Large \left(x-\frac{1}{x}\right)^{2} = x^{2}+\frac{1}{x^{2}}-2 \)

= 102 -2 = 100

\( \Large x-\frac{1}{x} = \sqrt{100} = 10 \)