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A pipe P can fill a tank in 12 min and another pipe R can fill it in 15 min. But, the 3rd pipe M can empty it in 6 min. The 1st two pipes P and R are kept open for double the 2.5 min in the beginning and then the 3rd pipe is also opened. In what time is the tank emptied?
A) 30 min
B) 25 min
C) 45 min
D) 35 min
Correct answer:
C) 45 min
Description for Correct answer:
According to the question,
Double the 2.5 min = 5 min
Now, part filled in 5 min
= \( \Large 5 \times \left(\frac{1}{12}+\frac{1}{15}\right) = 5 \times \left(\frac{5+4}{60}\right) \)
= \( \Large 5 \times \frac{9}{60} = \frac{3}{4} \)
Part emptied in 1 min when R R and all are opened.
= \( \Large \frac{1}{6}- \left(\frac{1}{12}+\frac{1}{15}\right)=\frac{1}{6}- \left(\frac{5+4}{60}\right) \)
=\( \Large \left(\frac{1}{6}-\frac{3}{2}\right)=\frac{1}{60} \)
One-sixtieth part is emptied in 1 min.
Therefore, Three-fourth part will be emptied in\( \Large 60 \times \frac{3}{4}=15 \times 3 \) = 45 min.
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