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Pipe A can fill a tank in 4 minutes. Pipe B can fill the same tank in 8 minutes. Pipe C at the bottom of the tank can drain the tank completely in 6 minutes. If all three pipes are kept open together when the tank is empty and pipe C is shut after 3 minutes, in how many minutes will the tank be full after Pipe C is shut?
A) 3 minutes
B) 5 minutes
C) 1 minute
D) 2 minutes
Correct answer:
C) 1 minute
Description for Correct answer:
During the first 3 minutes all 3 pipes are open. i.e.\( \Large \left(\frac{3}{4}+\frac{3}{8}-\frac{3}{6}\right) \)th = \( \Large \frac{18+9-12}{24}=\frac{15}{24} \)th of the lank will be full.
Then Pipe C is shut. Pipe A and Pipe B will fill \( \Large \frac{1}{4}+\frac{1}{8}=\frac{3}{8} \)th of the tank every minute.
As \( \Large \frac{15}{24} \)th of the tank is already full, Pipes A and B together have to fill
= \( \Large 1 - \frac{15}{24}=\frac{9}{24}=\frac{3}{8} \)th of the tank.
Therefore, it will take another 1 minute, after Pipe C is shut, to fill the tank.
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