Description for Correct answer:


\( \Large FM = \sqrt{ \left(3\right)^{2}- \left(\frac{3}{2}\right)^{2} } = \sqrt{9-\frac{9}{4}} = \frac{\sqrt{27}}{2} \)

Now FO : OM = 2 : 1

\( \Large \therefore\ \frac{\sqrt{27}}{2}=2x+1x \)

\( \Large \frac{3\sqrt{3}}{2}=3x \)

\( \Large \therefore\ x = \frac{\sqrt{3}}{2} \)

\( \Large \therefore\ FO = 2x = 2 \times \frac{\sqrt{3}}{2} \)

=> \( \Large FO = \sqrt{3} = r \)

Therefore, Hene radius of circle is \( \Large \sqrt{3}\ cm \)