Description for Correct answer:
Given : AC = 70 cm and BM = 27 cm



Therefore, Area of parallelogram ABCD

= \( \Large Area\ of\ \triangle ABC + Area\ of\ \triangle ACD \)

\( \Large \left(\frac{1}{2} \times 70 \times 27+\frac{1}{2} \times 70 \times 27\right)cm^{2} \)

\( \Large = 1890\ cm^{2} \)