Area of a rhombus = \( \Large \frac{1}{2} \times \ products\ of\ its\ diagonals \)

Therefore, \( \Large 120 = \frac{1}{2} \times 10 \times \ second\ diagonal \)

=> second diagonal = 24 cm D



From the figure,

\( \Large AB = \sqrt{12^{2}+5^{2}} \)

= \( \Large \sqrt{169} = 13\ cm \)