Given : \( \Large d_{1}=16\ cm,\ d_{2}=12\ cm \)

Side of rhombus = \( \Large \frac{1}{2}\sqrt{d^{2}_{1}+d^{2}_{2}} \)

= \( \Large \frac{1}{2}\sqrt{16^{2}+12^{2}} \)

= \( \Large \frac{1}{2}\sqrt{400} \)

= \( \Large \frac{1}{2} \times 20 = 10\ cm \)