The radius of the circle passing through the point \( \Large \left(6,\ 2\right) \) and two of whose diameter are \( \Large x+y=6\ and\ x+2y=4 \) is:

A) 4
B) 6

C) 20
D) \( \Large \sqrt{20} \)

Correct answer:
D) \( \Large \sqrt{20} \)

Description for Correct answer:
Centre is the point of intersection of two diameters i.e., the point of intersection of two diameter is \( \Large C \left(8,\ -2\right) \) therefore the distance from the centre to the point \( \Large P \left(6,\ 2\right) \) is

\( \Large r = CP = \sqrt{4+16} = \sqrt{20} \)

Please provide the error details in above question

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