The solution of the quadratic equation \( \Large \left(3|x|-3\right)^{2}=|x|+7 \) which belongs to the domain of definition of function \( \Large \gamma = \sqrt{x \left(x-3\right) } \) are given by:

A) \( \Large \pm \frac{1}{9}, \pm 2 \)

B) \( \Large -\frac{1}{9}, 2 \)

C) \( \Large \frac{1}{9}, -2 \)

D) \( \Large -\frac{1}{9}, -2 \)

Correct answer:
D) \( \Large -\frac{1}{9}, -2 \)

Description for Correct answer:

Domain of the function \( \Large y = \sqrt{x \left(x-3\right) } \) is \( \Large x \left(x-3\right)\ge 0 \)

=> \( \Large x < 0 \  or\ x > 3 \) ...(i)

Given equation can be rewritten as.

\( \Large 9|x|^{2} - 19|x|+2=0 \)

=> \( \Large \left(9|x|-1\right) \left(|x|-2\right)=0 \)

=> \( \Large |x|=2 \  or\ |x| = \frac{1}{9} \)

Therefore, Solution of given equation are \( \Large \pm 2, \pm \frac{1}{9} \) in the domain (i) the required solutions are \( \Large -2, - \frac{1}{9} \)



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