The number which exceeds its positive Square roots by 12 is:

A) 9

B) 16

C) 25

D) none of these

Correct answer:
B) 16

Description for Correct answer:
Let the required number is x

According to given condition

\( \Large x=\sqrt{x}+12 => x-12=\sqrt{x} \)

=> \( \Large x^{2}-25x+144=0 \)

=> \( \Large x^{2}-16x-9x+144=0 \)

Therefore, x = 16, 9

since x = 9 does not hold the condition

Therefore, x = 16


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