The given equations are

\( \Large qx^{2}+px+q=0 \)

and \( \Large x^{2}-4qx+p_{2}=0 \)

Since, root of the equation (i) are complex, therefore \( \Large P^{2}-4q^{2}<0 \). Now, discriminant or equation (ii) is \( \Large 16q^{2}-4 P^{2}=-4 \left(P^{2}-4q^{2}\right)>0 \) Hence, roots are real and unequal.