From the top of a light house 60 m high with its base at the sea level the angle of depression of a boat is \( \Large 15 ^{\circ} \). The distance of the boat from the foot of light house is:

A) \( \Large \left(\frac{\sqrt{3}-1}{\sqrt{3}+1}\right)60 m \)
B) \( \Large \frac{\sqrt{3+1}}{\sqrt{3-1}} m \)

C) \( \Large \left(\frac{\sqrt{3}-1}{\sqrt{3}+1}\right)60 m \)
D) none of therse

Correct answer:
B) \( \Large \frac{\sqrt{3+1}}{\sqrt{3-1}} m \)

Description for Correct answer:
Let BC be the light house.

In \( \Large \triangle ABC, \tan 15 ^{\circ} = \frac{60}{d} \)



=> \( \Large d = 60 \cot 15 ^{\circ} = 60 \left(\frac{\sqrt{3}+1}{\sqrt{3}-1}\right) m \)

Please provide the error details in above question

Recent Activities
Home About Us Terms and Conditions Privacy Policy Contact us