If \( \Large log_{e} \left(\frac{a+b}{2}\right) = \frac{1}{2} \left(log_{e} a+log_{e} b\right) \) then:

A) a = b

B) a = b/2

C) 2a = b

D) \( \Large a = \frac{b}{3} \)

Correct answer:
A) a = b

Description for Correct answer:

\( \Large log \left(\frac{a+b}{2}\right) = \frac{1}{2} \left(log_{e}a + log_{e}b\right) \)

=> \( \Large \frac{a+b}{2} = \sqrt{ab} \)

=> \( \Large a+b-2\sqrt{ab} = 0 \)

=> \( \Large \sqrt{a} = \sqrt{b} => a = b \)



Please provide the error details in above question